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प्रश्न
In the following figure, BA is parallel to CD. Find the angles a, b and c:
उत्तर
In the given figure,
ABC is a triangle and AB || DC and AC is its transversal.
∠BAC = ∠ACD (Alternate angles)
⇒ b = 65°
Again AB || DC and BCE is its transversal
∴ ∠ABC = ∠DCE
⇒ C = 70°
But ∠ACB + ∠ACD + ∠DCE = 180 (Straight line angle)
∴ a + 65° + 70° = 180°
⇒ a + 135° = 180°
⇒ a = 180° - 135° = 45°
Hence a = 45°, b = 65° and c = 70°
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