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In the following situation, involved make an arithmetic progression? and why? The cost of digging a well after every metre of digging, - Mathematics

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प्रश्न

In the following situation, involved make an arithmetic progression? and why?

The cost of digging a well after every metre of digging, when it costs Rs 150 for the first metre and rises by Rs 50 for each subsequent metre.

योग

उत्तर

Cost of digging for first metre = 150

Cost of digging for first 2 metres = 150 + 50 = 200

Cost of digging for first 3 metres = 200 + 50 = 250

Cost of digging for first 4 metres = 250 + 50 = 300

Clearly, 150, 200, 250, 300 … 

Check:

a = 150

d1 - a2 - a1

= 200 - 150

= 50

d2 = a3 - a2

= 250 - 200

= 50

d3 = a4 - a3

= 300 - 250

= 50

Common difference = 50

Here the common difference is the same hence this series is A.P.

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अध्याय 5: Arithmetic Progressions - Exercise 5.1 [पृष्ठ ९९]

APPEARS IN

एनसीईआरटी Mathematics [English] Class 10
अध्याय 5 Arithmetic Progressions
Exercise 5.1 | Q 1.3 | पृष्ठ ९९

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