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प्रश्न
In the given figure, AC is the diameter of the circle with centre O. If ∠ADE = 30°, ∠DAC = 35° and ∠CAB = 40°. Find ∠ACB
योग
उत्तर
∠ABC = 90° ...(Angle in a semi−circle)
∠ACB + ∠CBA + ∠BAC = 180° ...(Sum of the angles of a triangle is 180°)
∠ACB + 90° + 40° = 180°
∠ACB = 180° – 130°
= 50°
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Exterior Angle of a Cyclic Quadrilateral
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 4: Geometry - Exercise 4.4 [पृष्ठ १७३]
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