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Question
In the given figure, AC is the diameter of the circle with centre O. If ∠ADE = 30°, ∠DAC = 35° and ∠CAB = 40°. Find ∠ACB
Sum
Solution
∠ABC = 90° ...(Angle in a semi−circle)
∠ACB + ∠CBA + ∠BAC = 180° ...(Sum of the angles of a triangle is 180°)
∠ACB + 90° + 40° = 180°
∠ACB = 180° – 130°
= 50°
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Exterior Angle of a Cyclic Quadrilateral
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Chapter 4: Geometry - Exercise 4.4 [Page 173]
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