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Question
In the figure, ABCD is a cyclic quadrilateral in which DC produced to E and CF is drawn parallel to AB such that ∠ADC = 80° and ∠ECF = 20°, then BAD =?
Options
100°
20°
120°
110°
MCQ
Solution
120°
Explanation;
Hint:
∠BAD = ∠ABC + ∠ECF ...(By exterior angle property)
= 100° + 20°
= 120°
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Exterior Angle of a Cyclic Quadrilateral
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