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Question
AD is a diameter of a circle and AB is a chord If AD = 30 cm and AB = 24 cm then the distance of AB from the centre of the circle is
Options
10 cm
9 cm
8 cm
6 cm
Solution
9 cm
Explanation;
Hint:
In ΔAOC,
AO = 15 cm
AC = `1/2` AB
= `1/2 xx 24`
= 12 cm
In ΔAOC,
OC2 = AO2 – AC2
= 152 – 122
= 225 – 144
= 81
OC = `sqrt(81)`
= 9 cm
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