Advertisements
Advertisements
प्रश्न
In the given figure, PQRS is a parallelogram in which PA = AB = Prove that: SAQB is a parallelogram.
उत्तर
Construction:
Join BS and AQ.
Join diagonal QS.
Since diagonals of a parallelogram bisect each other.
∴ OP = OR and OQ = OS
Also, PA = AB = BR
Now, OP = OR and PA = PB
⇒ OP - PA = OR - PB
⇒ OA = OB
Thus, in quadrilateral SAQB, we have
OQ = OS and OA = OB
⇒ Diagonals of a quadrilateral SAQB bisect each other.
⇒ SAQB is a parallelogram.
APPEARS IN
संबंधित प्रश्न
PQRS is a parallelogram. PQ is produced to T so that PQ = QT. Prove that PQ = QT. Prove that ST bisects QR.
Prove that if the diagonals of a parallelogram are equal then it is a rectangle.
ABCD is a quadrilateral P, Q, R and S are the mid-points of AB, BC, CD and AD. Prove that PQRS is a parallelogram.
PQRS is a parallelogram. T is the mid-point of RS and M is a point on the diagonal PR such that MR = `(1)/(4)"PR"`. TM is joined and extended to cut QR at N. Prove that QN = RN.
In a parallelogram PQRS, M and N are the midpoints of the opposite sides PQ and RS respectively. Prove that
MN bisects QS.
In the given figure, PQRS is a trapezium in which PQ ‖ SR and PS = QR. Prove that: ∠PSR = ∠QRS and ∠SPQ = ∠RQP
PQRS is a parallelogram and O is any point in its interior. Prove that: area(ΔPOQ) + area(ΔROS) - area(ΔQOR) + area(ΔSOP) = `(1)/(2)`area(|| gm PQRS)
In the given figure, AB ∥ SQ ∥ DC and AD ∥ PR ∥ BC. If the area of quadrilateral ABCD is 24 square units, find the area of quadrilateral PQRS.
In the given figure, PQ ∥ SR ∥ MN, PS ∥ QM and SM ∥ PN. Prove that: ar. (SMNT) = ar. (PQRS).
In the figure, ABCD is a parallelogram and CP is parallel to DB. Prove that: Area of OBPC = `(3)/(4)"area of ABCD"`