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प्रश्न
Integrate the following with respect to x.
`(sqrt(2x) - 1/sqrt(2x))^2`
उत्तर
= `int[(sqrt(2x))^2 - 2(sqrt(2x)) (1/sqrt(2x)) + (1/sqrt(2x))^2] "d"x`
= `int (2x - 2 + 1/(2x)) "d"x`
= `2(x^2/2) - 2x + 1/2 log |x| + "c"`
= `x^2 - 2x + 1/2 log |x| + "c"`
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