Advertisements
Advertisements
प्रश्न
Integrate the following with respect to x.
`1/sqrt(x^2 - 3x + 2)`
उत्तर
`int ("d"x)/sqrt(x^2 - 3x + 2) = int ("d"x)/sqrt((x - 3/2)^2 - 9/4 + 2)``
= `int ("d"x)/sqrt((x - 3/2)^2 - (1/2)^2`
= `log|(x - 3/2) + sqrt((x - 3/2)^2 - (1/2)^2)| + "c"`
= `log|(x + 3/2) + sqrt(x^2 - 3x + 2)| + "c"`
APPEARS IN
संबंधित प्रश्न
Integrate the following with respect to x.
`(9x^2 - 4/x^2)^2`
Integrate the following with respect to x.
`(x^3 + 3x^2 - 7x + 11)/(x + 5)`
Integrate the following with respect to x.
`(3x^2 - 2x + 5)/((x - 1)(x^2 + 5))`
Integrate the following with respect to x.
`1/(x(log x)^2`
Integrate the following with respect to x.
`x^5 "e"^x`
Integrate the following with respect to x.
`("e"^(3logx))/(x^4 + 1)`
Integrate the following with respect to x.
`sqrt(2x^2 + 4x + 1)`
Choose the correct alternative:
`int sqrt("e"^x) "d"x` is
Choose the correct alternative:
`int (2x + 3)/sqrt(x^2 + 3x + 2) "d"x` is
Evaluate the following integral:
`int log (x - sqrt(x^2 - 1)) "d"x`
