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प्रश्न
Integrate the following with respect to x.
`1/sqrt(x^2 - 3x + 2)`
उत्तर
`int ("d"x)/sqrt(x^2 - 3x + 2) = int ("d"x)/sqrt((x - 3/2)^2 - 9/4 + 2)``
= `int ("d"x)/sqrt((x - 3/2)^2 - (1/2)^2`
= `log|(x - 3/2) + sqrt((x - 3/2)^2 - (1/2)^2)| + "c"`
= `log|(x + 3/2) + sqrt(x^2 - 3x + 2)| + "c"`
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