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प्रश्न
Integrate the following with respect to x.
`[1 - 1/2]"e"^((x + 1/x))`
उत्तर
= `int (1 - 1/x^2) "e"^((x + 1/x)) "d"x`
= `int "e"^((x + 1/x)) (1 - 1/x^2) "d"x`
= `int "e"^((x + 1/x)) "d" (x + 1/x)`
= `"e"^(x + 1/x) + "c"`
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