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Integrate the following with respect to x. 1x+x2-1 - Business Mathematics and Statistics

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प्रश्न

Integrate the following with respect to x.

`1/(x + sqrt(x^2 - 1)`

योग

उत्तर

`int 1/(x + sqrt(x^2 - 1))  "d"x`

By rationalisation

= `int (1 xx (x - sqrt(x^2 - 1)))/((x + sqrt(x^2 - 1)) xx (x - sqrt(x^2 - 1)))  "d"x`

= `int ((x - sqrt(x^2 - 1)))/((x^2) - (sqrt(x^2 - 1)^2))  "d"x`

= `int ((x - sqrt(x^2 - 1)))/(x^2 - (x^2 - 1))  "d"x`

= `int (x - sqrt(x^2 - 1))/(x^2 - x^2 + 1)  "d"x`

= `int (x - sqrt(x^2 - 1))  "d"x`

= `int x  "d"x - int sqrt(x^2 - 1)  "d"x`

= `x^2/2 - {x/2 sqrt(x^2 - 1) - (1)^2/2 log|x + sqrt(x^2 - 1)|} + "c"`

= `x^2/2 - x/2 sqrt(x^2 - 1) + 1/2 log|x + sqrt(x^2 - 1)| + "c"`

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Indefinite Integrals
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 2: Integral Calculus – 1 - Exercise 2.7 [पृष्ठ ४२]

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सामाचीर कलवी Business Mathematics and Statistics [English] Class 12 TN Board
अध्याय 2 Integral Calculus – 1
Exercise 2.7 | Q 16 | पृष्ठ ४२
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