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प्रश्न
Integrate the following with respect to x :
`(sin^-1 x)/sqrt(1 - x^2)`
उत्तर
`int (sin^-1 x)/sqrt(1 - x^2) "d"x`
`sin^-1x` = u
`1/sqrt(1 - x^2) "d"x` = du
`int (sin^-1x)/sqrt(1 - x^2) "d"x = int "u" * "du"`
= `"u"^2/2 + "c"`
`int (sin^-1x)/sqrt(1 - x^2) "d"x = (sin^-1x)^2/2 + "c"`
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