Advertisements
Advertisements
प्रश्न
Is it possible to have a polygon whose sum of interior angles is 7 right angles?
उत्तर
Let the number of sides in the polygon be n.
∴ (n - 2) x 180° = 7 Right Angles
⇒ (n - 2) x 180° = 7 x 90°
⇒ 180°n - 360° = 630°
⇒ 180°n = 990°
⇒ n = `(990°)/(180°)`
= `(11)/(2)`
= `5(1)/(2)`
Since the number of sides of a polygon cannot be in a fraction, therefore the polygon is not possible.
APPEARS IN
संबंधित प्रश्न
The difference between an exterior angle of (n - 1) sided regular polygon and an exterior angle of (n + 2) sided regular polygon is 6° find the value of n.
The ratio between an exterior angle and an interior angle of a regular polygon is 2 : 3. Find the number of sides in the polygon.
In a parallelogram ABCD, AB = 20 cm and AD = 12 cm. The bisector of angle A meets DC at E and BC produced at F.
Find the length of CF.
Find the sum of the interior angles of a polygon of: 7 sides
Find the sum of the interior angles of a polygon of: 9 sides
Find the measure of each interior angle of a regular polygon of: 10 sides
Find the measure of each interior angle of a regular polygon of: 15 sides
Find the value of each angle of a heptagon If three of its angles measure 132° each and the remaining four.
The number angle of a regular polygon is double the exterior angle. Find the number of sides of the polygon.
In a regular pentagon PQRST, PR = QT intersect at N. Find the angle RQT and QNP.