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Mr. Pradip Deposited Rs 2,400 Pm in Bank for One Year 6 Months Under the Recurring Deposit Scheme. If the Maturity Value of His Deposit is Rs 47,304 Find the Rate of Interest per Annum. - Mathematics

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प्रश्न

Mr. Pradip deposited  Rs 2,400 pm in bank for One year 6 months under the recurring deposit scheme. If the maturity value of his deposit is Rs 47,304 find the rate of interest per annum.

योग

उत्तर

Given that Recurring deposit per month =Rs 2400, Period= 3 years = 18

Months, R=R % , Maturity value =Rs 47304

Money deposited= Monthly value x No of Months= 2400 x 18=Rs 43,200

⇒  Interest= Maturity Value - Amount deposited 

=Rs (47,304- 43,200) =Rs 4,104

Total Principal for 1 Month = 2400 x (18)(18+1)/2= Rs 4,10,400

⇒  4104 = 410400 x R /1200 ~ R= 12 % 

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अध्याय 3: Banking - Exercise 3.2 [पृष्ठ ५१]

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फ्रैंक Mathematics - Part 2 [English] Class 10 ICSE
अध्याय 3 Banking
Exercise 3.2 | Q 10 | पृष्ठ ५१

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