मराठी

Mr. Pradip Deposited Rs 2,400 Pm in Bank for One Year 6 Months Under the Recurring Deposit Scheme. If the Maturity Value of His Deposit is Rs 47,304 Find the Rate of Interest per Annum. - Mathematics

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प्रश्न

Mr. Pradip deposited  Rs 2,400 pm in bank for One year 6 months under the recurring deposit scheme. If the maturity value of his deposit is Rs 47,304 find the rate of interest per annum.

बेरीज

उत्तर

Given that Recurring deposit per month =Rs 2400, Period= 3 years = 18

Months, R=R % , Maturity value =Rs 47304

Money deposited= Monthly value x No of Months= 2400 x 18=Rs 43,200

⇒  Interest= Maturity Value - Amount deposited 

=Rs (47,304- 43,200) =Rs 4,104

Total Principal for 1 Month = 2400 x (18)(18+1)/2= Rs 4,10,400

⇒  4104 = 410400 x R /1200 ~ R= 12 % 

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पाठ 3: Banking - Exercise 3.2 [पृष्ठ ५१]

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फ्रँक Mathematics - Part 2 [English] Class 10 ICSE
पाठ 3 Banking
Exercise 3.2 | Q 10 | पृष्ठ ५१

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