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Mr. Pradip Deposited Rs 2,400 Pm in Bank for One Year 6 Months Under the Recurring Deposit Scheme. If the Maturity Value of His Deposit is Rs 47,304 Find the Rate of Interest per Annum. - Mathematics

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Question

Mr. Pradip deposited  Rs 2,400 pm in bank for One year 6 months under the recurring deposit scheme. If the maturity value of his deposit is Rs 47,304 find the rate of interest per annum.

Sum

Solution

Given that Recurring deposit per month =Rs 2400, Period= 3 years = 18

Months, R=R % , Maturity value =Rs 47304

Money deposited= Monthly value x No of Months= 2400 x 18=Rs 43,200

⇒  Interest= Maturity Value - Amount deposited 

=Rs (47,304- 43,200) =Rs 4,104

Total Principal for 1 Month = 2400 x (18)(18+1)/2= Rs 4,10,400

⇒  4104 = 410400 x R /1200 ~ R= 12 % 

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Chapter 3: Banking - Exercise 3.2 [Page 51]

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Frank Mathematics - Part 2 [English] Class 10 ICSE
Chapter 3 Banking
Exercise 3.2 | Q 10 | Page 51

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