Advertisements
Advertisements
प्रश्न
Multiple choice Question. Select the correct option.
The distance covered in the adjoining velocity-time graph is :
विकल्प
25 m
40 m
50 m
45 m
उत्तर
50 m
Explanation:
Distance covered = Area under velocity – time graph
=1/2 × base × height
a = 1/2 × 5 × 20 = 50 m
APPEARS IN
संबंधित प्रश्न
The velocity-time graph for part of a train journey is a horizontal straight line. What does this tell you about its acceleration ?
What can you say about the motion of a body if:
its velocity-time graph is a straight line ?
Given alongside is the velocity-time graph for a moving body :
Find :
(i) Velocity of the body at point C.
(ii) Acceleration acting on the body between A and B.
(iii) Acceleration acting on the body between B and C.
Draw a displacement-time graph for a boy going to school with uniform velocity.
From the displacement-time graph of a cyclist given below in the Figure, find The time after which he reaches the starting point .
The area of the right triangle under a speed-time graph is 500 m, in a time interval of 20 s. What is the speed of the body? Is the motion uniform or non-uniform?
Draw the speed-time graph of a body starting from some point P, gradually picking up speed, then running at a uniform speed and finally slowing down to stop at some point Q.
Draw velocity-time graph to show:
Deceleration
Write a sentence to explain the shape of graph.
The slope of the speed–time graph gives ______.
The area under velocity – time graph represents the ______
