Advertisements
Advertisements
प्रश्न
Multiply (4x2 + 9) and (3x – 2)
उत्तर
(4x2 + 9)(3x – 2) = 4x2(3x – 2) + 9(3x – 2)
= (4x2)(3x) – (4x2)(2) + 9(3x) – 9(2)
= (4 × 3 × x × x2) – (4 × 2 × x2) + (9 × 3 × x) – 18
= 12x3 – 8x2 + 27x – 18(4x3 + 9)(3x – 2)
= 12x3 – 8x2 + 27x – 18
APPEARS IN
संबंधित प्रश्न
Find the product of the following pair of monomial.
4p, 0
Complete the table of products.
|
First monomial→ |
2x |
–5y |
3x2 |
–4xy |
7x2y |
–9x2y2 |
|
Second monomial ↓ |
||||||
| 2x | 4x2 | ... | ... | ... | ... | ... |
| –5y | ... | ... | –15x2y | ... | ... | ... |
| 3x2 | ... | ... | ... | ... | ... | ... |
| – 4xy | ... | ... | ... | ... | ... | ... |
| 7x2y | ... | ... | ... | ... | ... | ... |
| –9x2y2 | ... | ... | ... | ... | ... | ... |
Obtain the volume of a rectangular box with the following length, breadth, and height, respectively.
5a, 3a2, 7a4
Express each of the following product as a monomials and verify the result for x = 1, y = 2:
(−xy3) × (yx3) × (xy)
Express each of the following product as a monomials and verify the result for x = 1, y = 2:
Multiply: 5a − 1 by 7a − 3
Multiply: `-2/3"a"^7"b"^2` and `-9/4"a""b"^5`
A total of 90 currency notes, consisting only of ₹ 5 and ₹ 10 denominations, amount to ₹ 500. Find the number of notes in each denomination.
Volume of a rectangular box (cuboid) with length = 2ab, breadth = 3ac and height = 2ac is ______.
Multiply the following:
6mn, 0mn
