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प्रश्न
Name the following organic compound:
The first homologue whose general formula is CnH2n.
उत्तर
Ethene
Explanation:
CnH2n is the general formula for the homologous series of alkenes. The first member of the alkene family is the compound having two carbon atoms which are known as ethene. Methene is not possible as at least two carbons are required for the formation of the double bond.
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संबंधित प्रश्न
Write the next homologue of the following: C4H6
Write the name and formula of the 2nd member of homologous series having general formula CnH2n – 2.
The molecular formula of a homologue of butane is:
(a) C4H8
(b) C3H6
(c) C4H6
(d) C3H8
The molecular formula of the third member of the homologous series of ketones is:
(a) C4H8O
(b) C3H6O
(c) C5H10O
(d) C6H12O
Saturated hydrocarbon : Single bond : : Unsaturated hydrocarbon : _______
Write a short note.
Homologous series
Complete the following chart by using examples given in brackets.
(isobutylene, cyclohexane, propane, cyclohexene, cyclopentane, benzene, propyne, isobutane, propene)
Straight chain hydrocarbons | Branched chain hydrocarbons | Cyclic hydrocarbons |
The first member of alkyne homologous series is
A carbon compound ‘A’ having melting point 156K and boiling point 351K, with molecular formula C2H6O is soluble in water in all proportions.
- Identify ‘A’ and draw its electron dot structure.
- Give the molecular formulae of any two homologues of ‘A’.
Consider the carbon compounds having following molecular formula:
(i) C2H2 (ii) C2H5 (iii) C3H7OH (iv) C2H6COOH (v) CH3CHO
- Identify which one of the above compounds, is a member of aldehyde series.
- Write the general formula of the series to which compound C2H2 belongs.
- Which one of the above compounds has triple bonds between carbon-carbon atoms?
- Write the molecular formula of the first member of the homologous series to which the compound C3H7OH belongs.