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Obtain a relation for the distance travelled by an object moving with a uniform acceleration in the interval between 4th and 5th seconds. - Science

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प्रश्न

Obtain a relation for the distance travelled by an object moving with uniform acceleration in the interval between 4th and 5th seconds.

संक्षेप में उत्तर

उत्तर

Let the object be moving with initial velocity u ms−1 and uniform acceleration an ms−2 

∴ The distance travelled by the moving object

in ts is, s = `"ut" + 1/2 "at"^2`

Now distance travelled in 4s,

s4 = `"u" xx 4 + 1/2 "a" xx 4^2`

= 4u + 8a

Distance travelled in 5s

s5 = `"u" xx 5 + 1/2 "a" xx 5^2`

= `5"u" + 25/2 "a"`

∴ Distance travelled in the interval between 4th and 5th second

= `(5"u" + 25/2 "a") - (4"u" + 8"a")`

= `("u" + 9/2"a")"m"`

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अध्याय 8: Motion - Short Answer Questions [पृष्ठ ६०]

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एनसीईआरटी एक्झांप्लर Science [English] Class 9
अध्याय 8 Motion
Short Answer Questions | Q 23. | पृष्ठ ६०

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