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Obtain a relation for the distance travelled by an object moving with a uniform acceleration in the interval between 4th and 5th seconds. - Science

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Question

Obtain a relation for the distance travelled by an object moving with uniform acceleration in the interval between 4th and 5th seconds.

Answer in Brief

Solution

Let the object be moving with initial velocity u ms−1 and uniform acceleration an ms−2 

∴ The distance travelled by the moving object

in ts is, s = `"ut" + 1/2 "at"^2`

Now distance travelled in 4s,

s4 = `"u" xx 4 + 1/2 "a" xx 4^2`

= 4u + 8a

Distance travelled in 5s

s5 = `"u" xx 5 + 1/2 "a" xx 5^2`

= `5"u" + 25/2 "a"`

∴ Distance travelled in the interval between 4th and 5th second

= `(5"u" + 25/2 "a") - (4"u" + 8"a")`

= `("u" + 9/2"a")"m"`

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Chapter 8: Motion - Short Answer Questions [Page 60]

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NCERT Exemplar Science [English] Class 9
Chapter 8 Motion
Short Answer Questions | Q 23. | Page 60

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