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प्रश्न
Obtain the equation of the line containing the point: (2, 5) and perpendicular to the X−axis.
उत्तर
Equation of a line perpendicular to X-axis
i.e., parallel to Y-axis, is of the form x = h.
Since, the line passes through (2, 5).
∴ h = 2
∴ the equation of the required line is x = 2.
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संबंधित प्रश्न
Find the slope of the following lines which pass through the point: (– 2, 3), (5, 7)
Find the slope of the line whose inclination is 30°.
Find the slope of the line whose inclination is 45°.
Without using Pythagoras theorem, show that points A (4, 4), B (3, 5) and C (– 1, – 1) are the vertices of a right-angled triangle.
Find the value of k for which the points P(k, – 1), Q(2, 1) and R(4, 5) are collinear.
Find the slope of the line passing through the following point: (1, 2), (3, – 5)
Find the slope of the line passing through the following point: (1, 3), (5, 2)
Find the slope of the line passing through the following point: (–1, 3), (3, –1)
Find the slope of the line which makes an angle of 120° with the positive X-axis.
Find the slope of the line which makes intercepts 3 and – 4 on the axes.
Find the slope of the line which passes through the points A(–2, 1) and the origin.
Find the value of k: the points (1, 3), (4, 1), (3, k) are collinear.
Find the slope of the line y – x + 3 = 0.
Does point A(2, 3) lie on the line 3x + 2y – 6 = 0? Give reason.
Find the equation of the line: containing the point T(7, 3) and having inclination 90°.
Find the equation of the line: containing the origin and having inclination 90°.
