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प्रश्न
Plot the points A(1, – 1) and B(4, 5). Extend this line segment and write the coordinates of a point on this line which lies outside the line segment AB.
उत्तर
In point A(1, – 1), x-coordinate is positive and y-coordinate is negative, so it lies in IV quadrant.
In point B(4, 5), both coordinates are positive, so it lies in I quadrant.
On plotting these point, we get the following graph.
Extent the line segment AB.
Now, draw a perpendicular to x-axis from x = 5, say it intersects extended line segment at Q.
Again, draw a perpendicular to y-axis from Q and it intersects y-axis at y = 7.
Thus, we get the point Q(5, 7) which lies outside the line segment AB.
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संबंधित प्रश्न
Plot the points (x, y) given in the following table on the plane, choosing suitable units of distance on the axes.
| x | -2 | -1 | 0 | 1 | 3 |
| y | 8 | 7 | -1.25 | 3 | -1 |
Plot the following point on the graph paper:
(0, 0)
Plot the following point on the graph paper:
(−5, −7)
Write down the abscissa and ordinate of the following.
S
Find the quadrants without plotting the point on a graph sheet.
(5, 7)
Plot the following point in a graph sheet.
D(−1, −1)
Find the quadrants without plotting the point on a graph sheet.
(−8, 0)
Find the quadrants without plotting the point on a graph sheet.
(0, 10)
Plot the following point in a graph sheet.
J(8, −4)
Plot the points (x, y) given by the following table. Use scale 1 cm = 0.25 units
| x | 1.25 | 0.25 | 1.5 | – 1.75 |
| y | – 0.5 | 1 | 1.5 | – 0.25 |
