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Question
Plot the points A(1, – 1) and B(4, 5). Extend this line segment and write the coordinates of a point on this line which lies outside the line segment AB.
Solution
In point A(1, – 1), x-coordinate is positive and y-coordinate is negative, so it lies in IV quadrant.
In point B(4, 5), both coordinates are positive, so it lies in I quadrant.
On plotting these point, we get the following graph.
Extent the line segment AB.
Now, draw a perpendicular to x-axis from x = 5, say it intersects extended line segment at Q.
Again, draw a perpendicular to y-axis from Q and it intersects y-axis at y = 7.
Thus, we get the point Q(5, 7) which lies outside the line segment AB.
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