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प्रश्न
Population of a city in the years 2005 and 2010 are 1,35,000 and 1,45,000 respectively. Find the approximate population in the year 2015. (assuming that the growth of population is constant)
उत्तर
Let us choose the year along the x-axis and the population of the city along the y-axis.
Given In the year 2005 population is 1,35,000
The corresponding point is (2005, 1,35,000)
In the year 2010, population is 1,45,000
The corresponding point is (2010, 1,45,000)
Let Y denote the year and P denote the population.
The relation connecting Y and P is the equation of the straight line joining the points (2005, 1,35,000) and (2010, 1,45,000)
`("Y" - 2005)/(2010 - 2005) = ("P" - 135000)/(1445000 - 135 000)`
`("Y" - 2005)/5 = ("P" - 135000)/10000`
When y = 2015
2015 – 2005 = `("P" - 135000)/2000`
10 = `("P" - 135000)/2000`
P = 135000 + 10 × 2000
P = 135000 + 20000 = 155000
∴ The population in the year 2015 is 1,55,000
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