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प्रश्न
Rationalise the denominator of each of the following
`1/sqrt12`
उत्तर
We know that rationalization factor for `1/sqrta` is `sqrta`. We will multiply numerator and denominator of the given expression `1/sqrt12` by `sqrt12` to get
`1/sqrt12 xx sqrt12/sqrt12 = sqrt12/(sqrt12 xx sqrt12)`
`= sqrt12/12`
`= (sqrt4 xx sqrt3)/12`
`= (2 xx sqrt3) /12`
`= sqrt3/6`
Hence the given expression is simplified to `sqrt3/6`
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संबंधित प्रश्न
Find the value to three places of decimals of the following. It is given that
`sqrt2 = 1.414`, `sqrt3 = 1.732`, `sqrt5 = 2.236` and `sqrt10 = 3.162`
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Find the value to three places of decimals of the following. It is given that
`sqrt2 = 1.414`, `sqrt3 = 1.732`, `sqrt5 = 2.236` and `sqrt10 = 3.162`
`(sqrt5 + 1)/sqrt2`
Find the values the following correct to three places of decimals, it being given that `sqrt2 = 1.4142`, `sqrt3 = 1.732`, `sqrt5 = 2.2360`, `sqrt6 = 2.4495` and `sqrt10 = 3.162`
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if `x = (sqrt3 + 1)/2` find the value of `4x^2 +2x^2 - 8x + 7`
If\[\frac{\sqrt{3} - 1}{\sqrt{3} + 1} = x + y\sqrt{3},\] find the values of x and y.
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Rationalise the denominator in the following and hence evaluate by taking `sqrt(2) = 1.414, sqrt(3) = 1.732` and `sqrt(5) = 2.236`, upto three places of decimal.
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Simplify:
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