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प्रश्न
Read the following reaction and answer the questions given below:
- Write the name of the reaction.
- Identify the electrophile in it.
- How is this electrophile generated?
उत्तर
- The name of the reaction is Friedel-Craft’s alkylation reaction.
- The electrophile in the reaction is +CH3.
- The electrophile +CH3 is generated as follows:
\[\ce{\underset{\text{Methyl chloride}}{CH3 -}Cl + AlCl3 -> \underset{\text{Electrophile}}{^+CH3 +}AlCl^-_4}\]
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\phantom{..............................}\ce{CH3}\\
\phantom{...........................}|\\
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|\phantom{....................................}\\
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\phantom{..............................}\ce{CH3}\\
\phantom{...........................}|\\
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\[\begin{array}{cc}
\phantom{.............................}\ce{CH3}\\
\phantom{...........................}|\\
\ce{CH3 - C = CH2 + HBr ->[benzoyl][peroxide] CH3 - CH - CH2Br}\\
|\phantom{....................................}\\
\ce{CH3}\phantom{.................................}\\
\end{array}\]
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\[\begin{array}{cc}
\phantom{..............................}\ce{CH3}\\
\phantom{............................}|\\
\ce{CH3 - C = CH2 + HBr ->[benzoyl][peroxide] CH3 - CH - CH2Br}\\
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\[\begin{array}{cc}
\phantom{..............................}\ce{CH3}\\
\phantom{...........................}|\\
\ce{CH3 - C = CH2 + HBr ->[benzoyl][peroxide] CH3 - CH - CH2Br}\\
|\phantom{....................................}\\
\ce{CH3}\phantom{.................................}
\end{array}\]
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\[\begin{array}{cc}
\phantom{...............................}\ce{CH3}\\
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\ce{CH3 - C = CH2 + HBr ->[benzoyl][peroxide]CH3 - CH - CH2Br}\\
|\phantom{....................................}\\
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\[\begin{array}{cc}
\phantom{..............................}\ce{CH3}\\
\phantom{............................}|\\
\ce{CH3 - C = CH2 + HBr ->[benzoyl][peroxide]CH3 - CH - CH2Br}\\
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\ce{CH3}\phantom{.................................}
\end{array}\]
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\[\begin{array}{cc}
\phantom{..............................}\ce{CH3}\\
\phantom{............................}|\\
\ce{CH3 - C = CH2 + HBr ->[benzoyl][peroxide] CH3 - CH - CH2Br}\\
|\phantom{....................................}\\
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\end{array}\]
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