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प्रश्न
Show on a graph the variation of the de Broglie wavelength (λ) associated with an electron, with the square root of accelerating potential (V) ?
उत्तर
`lambda = 1.22/sqrtV`
`therefore lambda sqrtV=` const
Hence, we get a hyperbola.
संबंधित प्रश्न
Calculate the de-Broglie wavelength of an electron moving with one-fifth of the speed of light.Neglect relativistic effects. (`h = 6.63 xx 10^(-34)` J.s, c= `3xx10^8`m/s, mass of electron = `9 xx 10^(-31) kg)`
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