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प्रश्न
Show how is the following alcohol prepared by the reaction of a suitable Grignard reagent on methanal?
\[\begin{array}{cc}
\ce{CH3 - CH - CH2OH}\\
|\phantom{......}\\
\ce{CH3}\phantom{...}
\end{array}\]
उत्तर
\[\begin{array}{cc}
\phantom{..........}\ce{OMgBr}\\
\phantom{....}|\\
\ce{CH3 - CH - MgBr + HCHO -> CH3 - CH - CH2 ->[H2O] CH3 - CH - CH2OH + Mg(OH)Br}\\
|\phantom{.................................}|\phantom{......................}|\phantom{...................}\\
\phantom{.}\ce{CH3}\phantom{.............................}\ce{CH3}\phantom{...................}\ce{CH3}\phantom{.................}
\end{array}\]
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\[\begin{array}{cc}
\ce{Cl}\phantom{.........................}\\
|\phantom{..........................}\\
\ce{CH3 - CH - CH3 ->[(i) Alc. KOH][(ii) HBr/peroxide (iii) aq. KOH]}
\end{array}\]