Advertisements
Advertisements
प्रश्न
Show the 6n cannot end with digit 0 for any natural number 'n'.
उत्तर
Here, 6n = (2 × 3)n = 2n × 3n
∴ Only prime factorization of 6n are 2 and 3
But 6n, for any natural number n, ends with digit 0, then it must contain the prime numbers 5.
Hence, 6n can not end with digit 0 for any natural number 'n'.
संबंधित प्रश्न
Express the number as a product of its prime factor:
140
A merchant has 120 liters of oil of one kind, 180 liters of another kind and 240 liters of third kind. He wants to sell the oil by filling the three kinds of oil in tins of equal capacity. What should be the greatest capacity of such a tin?
Determine the prime factorisation of each of the following positive integer:
58500
Express the number as a product of its prime factor:
7429
The number in the form of 4p + 3, where p is a whole number, will always be ______.
If LCM(x, 18) = 36 and HCF(x, 18) = 2, then x is ______.
For some integer q, every odd integer is of the form ______.
If the HCF of 65 and 117 is expressible in the form 65m – 117, then the value of m is ______.
Statement A (Assertion): If product of two numbers is 5780 and their HCF is 17, then their LCM is 340.
Statement R (Reason): HCF is always a factor of LCM.
If n is a natural number, then 8n cannot end with digit