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Question
Show the 6n cannot end with digit 0 for any natural number 'n'.
Solution
Here, 6n = (2 × 3)n = 2n × 3n
∴ Only prime factorization of 6n are 2 and 3
But 6n, for any natural number n, ends with digit 0, then it must contain the prime numbers 5.
Hence, 6n can not end with digit 0 for any natural number 'n'.
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