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सी.आई.एस.सी.ई.आईसीएसई ICSE Class 7

Simplify: 3 3/7 Div 1 1/14 - Mathematics

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प्रश्न

Simplify: `3 3/7 div 1 1/14`

योग

उत्तर

`3 3/7 div 1 1/14`

`= 24/7 xx 14/15 = (24 xx 14)/(7 xx 15)`

`=336/105 = (336 div 21)/(105 div 21)` (HCF of 336 and 105 = 21)

`= 16/5 = 3 1/5`

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Concept for Fraction as an Operator
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अध्याय 3: Fractions (Including Problems) - Exercise 3 (C)

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सेलिना Concise Mathematics [English] Class 7 ICSE
अध्याय 3 Fractions (Including Problems)
Exercise 3 (C) | Q 2.12
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