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तमिलनाडु बोर्ड ऑफ सेकेंडरी एज्युकेशनएसएसएलसी (अंग्रेजी माध्यम) कक्षा १०

Simplify b2+3b-28b2+4b+4÷b2-49b2-5b-14 - Mathematics

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प्रश्न

Simplify `("b"^2 + 3"b" - 28)/("b"^2 + 4"b" + 4) ÷ ("b"^2 - 49)/("b"^2 - 5"b" - 14)`

योग

उत्तर


b2 + 3b – 28 = (b + 7) (b – 4)

b2 + 4b + 4 = (b + 2) (b + 2)

b2 – 49 = b2 – 72

= (b + 7) (b – 7)

b2 – 5b – 14 = (b – 7) (b + 2)



`("b"^2 + 3"b" - 28)/("b"^2 + 4"b" + 4) ÷ ("b"^2 - 49)/("b"^2 - 5"b" - 14)`

= `(("b" + 7)("b" - 4))/(("b" + 2)("b" + 2)) ÷ (("b" + 7)("b" - 7))/(("b" - 7)("b" + 2))`

= `(("b" + 7)("b" - 4))/(("b" + 2)("b" + 2)) xx (("b" + 2))/(("b" + 7))`

= `(("b" - 4))/(("b" + 2))`

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Rational Expressions
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 3: Algebra - Exercise 3.5 [पृष्ठ १०१]

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सामाचीर कलवी Mathematics [English] Class 10 SSLC TN Board
अध्याय 3 Algebra
Exercise 3.5 | Q 3. (ii) | पृष्ठ १०१

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