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प्रश्न
Simplify:
`(27"x"^-3"y"^6)^(2/3)`
योग
उत्तर
`(27"x"^-3"y"^6)^(2/3)=(27)^(2/3)."x"^(-3xx2/3)."y"^(6xx2/3`
`=(3xx3xx3)^(2/3)."x"^-2."y"^4`
`=[(3xx3xx3)^(1/3)]^2."x"^-2."y"^4`
`=3^2."x"^-2"y"^4`
`=9"x"^-2"y"^4`
`=(9"y"^4)/"x"^2=9"x"^-2"y"^4`
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