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प्रश्न
Simplify:
`("x"^(2"n"+7).("x"^2)^(3"n"+2))/"x"^(4(2"n"+3)`
योग
उत्तर
`("x"^(2"n"+7).("x"^2)^(3"n"+2))/"x"^(4(2"n"+3)`
Given expression`=("x"^(2"n"+7)."x"^(6"n"+4))/"x"^(8"n"+12`
`="x"^(2"n"+7+6"n"+4)/"x"^(8"n"+12)="x"^(8"n"+11)/"x"^(8"n"+12`
`="x"^(8"n"+11-8"n"-12)="x"^-1`
`=1/"x"`
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