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प्रश्न
Simplify:
`("a"^(2"n"+3)."a"^((2"n"+1)("n"+2)))/(("a"^3)^(2"n"+1)."a"^("n"(2"n"+1)`
योग
उत्तर
`("a"^(2"n"+3)."a"^((2"n"+1)("n"+2)))/(("a"^3)^(2"n"+1)."a"^("n"(2"n"+1))`
Given expression`=("a"^(2"n"+3)."a"^((2"n"^2+4"n"+"n"+2)))/("a"^(6"n"+3)."a"^(2"n"^2+"n"`
`="a"^(2"n"+3+2"n"^2+5"n"+2)/"a"^(6"n"+3+2"n"^2+"n")`
`="a"^(2"n"^2+7"n"+5)/"a"^(2"n"^2+7"n"+3`
`= a^(2n^2 +7n + 5 - 2n^2 - 7n - 3 )`
`= a^2`
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