Advertisements
Advertisements
Question
Simplify:
`("a"^(2"n"+3)."a"^((2"n"+1)("n"+2)))/(("a"^3)^(2"n"+1)."a"^("n"(2"n"+1)`
Solution
`("a"^(2"n"+3)."a"^((2"n"+1)("n"+2)))/(("a"^3)^(2"n"+1)."a"^("n"(2"n"+1))`
Given expression`=("a"^(2"n"+3)."a"^((2"n"^2+4"n"+"n"+2)))/("a"^(6"n"+3)."a"^(2"n"^2+"n"`
`="a"^(2"n"+3+2"n"^2+5"n"+2)/"a"^(6"n"+3+2"n"^2+"n")`
`="a"^(2"n"^2+7"n"+5)/"a"^(2"n"^2+7"n"+3`
`= a^(2n^2 +7n + 5 - 2n^2 - 7n - 3 )`
`= a^2`
APPEARS IN
RELATED QUESTIONS
Compute:
`(2/3)^(-4)xx(27/8)^-2`
Compute:
`(56/28)^0÷(2/5)^3xx16/25`
Compute:
`(-1/3)^4÷(-1/3)^8xx(-1/3)^5`
Evaluate:
`(-5)^0`
Simplify:
`"x"^10"y"^6÷"x"^3"y"^-2`
Simplify:
`5"z"^16÷15"z"^-11`
Simplify:
`(27"x"^-3"y"^6)^(2/3)`
Simplify and express as positive indice:
(xy)(m-n).(yz)(n-l).(zx)(l-m)
Evaluate:
`("a"^(2"n"+1)xx"a"^((2"n"+1)(2"n"-1)))/("a"^("n"(4"n"-1))xx("a"^2)^(2"n"+3)`
Find the value of n, when:
`("a"^(2"n"-3)xx("a"^2)^("n"+1))/(("a"^4)^-3)=("a"^3)^3÷("a"^6)^-3`
