Advertisements
Advertisements
Question
Compute:
`(56/28)^0÷(2/5)^3xx16/25`
Sum
Solution
`(56/28)^0÷(2/5)^3xx16/25`
=`1÷2^3/5^3xx(2xx2xx2xx2)/(5xx5)`
`[∵(56/28)^0=1]`
=`1xx5^3/2^3xx2^4/5^2=5^(3-2)xx2^(4-3)`
=`5^1xx2^1=10`
shaalaa.com
More About Exponents
Is there an error in this question or solution?
APPEARS IN
RELATED QUESTIONS
Compute:
`(4^7)^2xx(4^-3)^4`
Compute:
`(-1/3)^4÷(-1/3)^8xx(-1/3)^5`
Compute:
`(625)^(-3/4)`
Compute:
`(243)^(2/5)÷(32)^(-2/5)`
Simplify:
`8^(4/3)+25^(3/2)-(1/27)^(-2/3)`
Simplify:
`(2^-3-2^-4)(2^-3+2^-4)`
Evaluate:
`4"x"^0`
Simplify:
`(125"x"^-3)^(1/3)`
Evaluate:
`(x^(5+n)(x^2)^(3n+1))/x^(7n-2)`
Prove that:
`("m"+"n")^-1("m"^-1+"n"^-1)=("m""n")^-1`
