English

Evaluate: - Mathematics

Advertisements
Advertisements

Question

Evaluate:

`("a"^(2"n"+1)xx"a"^((2"n"+1)(2"n"-1)))/("a"^("n"(4"n"-1))xx("a"^2)^(2"n"+3)`

Sum

Solution

`("a"^(2"n"+1)xx"a"^((2"n"+1)(2"n"-1)))/("a"^("n"(4"n"-1))xx("a"^2)^(2"n"+3)`

`=("a"^(2"n"+1)xx"a"^((2"n")^2-(1)^2))/("a"^(4"n"^2-"n")xx"a"^(2(2"n+3)"`

`=("a"^(2"n"+1)xx"a"^(4"n"^2-1))/("a"^(4"n"^2-"n")xx"a"^(4"n"+6)`

`="a"^(2"n"+1+4"n"^2-1-4"n"^2+"n"-4"n"-6)`

`="a"^(-"n"-6)`

`="a"^-(-"n"+6)`

`=1/("a"^("n"+6)`

shaalaa.com
More About Exponents
  Is there an error in this question or solution?
Chapter 2: Exponents - Exercise 2 (B) [Page 34]

APPEARS IN

Selina Concise Mathematics [English] Class 8 ICSE
Chapter 2 Exponents
Exercise 2 (B) | Q 10 | Page 34
Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×