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प्रश्न
Evaluate:
`("a"^(2"n"+1)xx"a"^((2"n"+1)(2"n"-1)))/("a"^("n"(4"n"-1))xx("a"^2)^(2"n"+3)`
बेरीज
उत्तर
`("a"^(2"n"+1)xx"a"^((2"n"+1)(2"n"-1)))/("a"^("n"(4"n"-1))xx("a"^2)^(2"n"+3)`
`=("a"^(2"n"+1)xx"a"^((2"n")^2-(1)^2))/("a"^(4"n"^2-"n")xx"a"^(2(2"n+3)"`
`=("a"^(2"n"+1)xx"a"^(4"n"^2-1))/("a"^(4"n"^2-"n")xx"a"^(4"n"+6)`
`="a"^(2"n"+1+4"n"^2-1-4"n"^2+"n"-4"n"-6)`
`="a"^(-"n"-6)`
`="a"^-(-"n"+6)`
`=1/("a"^("n"+6)`
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