Advertisements
Advertisements
प्रश्न
Solve the following quadratic equation by Factorisation method: x2 + 7x + 10 = 0
उत्तर
x2 + 7x + 10 = 0
Splitting the middle term 7x as 2x + 5x, we get
x2 + 2x + 5x + 10 = 0
∴x(x + 2) + 5(x + 2) = 0
∴(x + 2)(x + 5) = 0
∴x + 2 = 0 or x + 5 = 0
∴x = –2 or x = –5
APPEARS IN
संबंधित प्रश्न
Find two numbers whose sum is 27 and product is 182.
Find the consecutive even integers whose squares have the sum 340.
A two digit number is 4 times the sum of its digits and twice the product of its digits. Find the number.
A train covers a distance of 90 km at a uniform speed. Had the speed been 15 km/hour more, it would have taken 30 minutes less for a journey. Find the original speed of the train.
Solve the following quadratic equation by factorization:
`sqrt(6)x^2 - 4x - 2sqrt(6) = 0`
Solve:
`1/(x + 1) - 2/(x + 2) = 3/(x + 3) - 4/(x + 4)`
The sum of natural number and its positive square root is 132. Find the number.
Solve the following quadratic equation for x:
`4sqrt3x^3+5x-2sqrt3=0`
The sum of two natural numbers is 20 while their difference is 4. Find the numbers.
If 1 is a root of the quadratic equation \[3 x^2 + ax - 2 = 0\] and the quadratic equation \[a( x^2 + 6x) - b = 0\] has equal roots, find the value of b.
If sin α and cos α are the roots of the equations ax2 + bx + c = 0, then b2 =
Solve the following equation: 4x2 + 4 bx - (a2 - b2) = 0
A two digit number is four times the sum and 3 times the product of its digits, find the number.
Rs. 480 is divided equally among ‘x’ children. If the number of children were 20 more then each would have got Rs. 12 less. Find ‘x’.
A shopkeeper purchases a certain number of books for Rs. 960. If the cost per book was Rs. 8 less, the number of books that could be purchased for Rs. 960 would be 4 more. Write an equation, taking the original cost of each book to be Rs. x, and Solve it to find the original cost of the books.
Solve the following equation by factorization
`(x^2 - 5x)/(2)` = 0
Solve the following equation by factorization
6p2+ 11p – 10 = 0
Find two consecutive odd integers such that the sum of their squares is 394.
Divide 16 into two parts such that the twice the square of the larger part exceeds the square of the smaller part by 164.
If the sum of the roots of the quadratic equation ky2 – 11y + (k – 23) = 0 is `13/21` more than the product of the roots, then find the value of k.
