Advertisements
Advertisements
प्रश्न
Solve the following quadratic equations by factorization:
(2x + 3)(3x − 7) = 0
उत्तर
We have,
(2x + 3)(3x − 7) = 0
⇒ (2x + 3) = 0 or (3x − 7) = 0
⇒ 2x = -3 or 3x = 7
⇒ x = -3/2 or x = 7/3
Thus, x = -3/2 and x = 7/3 are two roots of the equation (2x + 3)(3x − 7) = 0
APPEARS IN
संबंधित प्रश्न
Solve (i) x2 + 3x – 18 = 0
(ii) (x – 4) (5x + 2) = 0
(iii) 2x2 + ax – a2 = 0; where ‘a’ is a real number
Solve the following quadratic equations by factorization:
abx2 + (b2 – ac)x – bc = 0
The sum of the squares of two consecutive positive even numbers is 452. Find the numbers.
Solve the following quadratic equations by factorization:
\[9 x^2 - 6 b^2 x - \left( a^4 - b^4 \right) = 0\]
Show that x = −3 is a solution of x2 + 6x + 9 = 0.
Solve the following equation: `"x"^2 - ( sqrt 2 + 1) "x" + sqrt 2 = 0 `
A two digit number is such that the product of the digits is 14. When 45 is added to the number, then the digit are reversed. Find the number.
In each of the following determine whether the given values are solutions of the equation or not.
x2 + 6x + 5 = 0; x = -1, x = -5
Solve the following equation by factorization
`x^2/(15) - x/(3) - 10` = 0
Solve the quadratic equation by factorisation method:
x2 – 15x + 54 = 0
