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प्रश्न
Solve the following quadratic equations by factorization:
ax2 + (4a2 - 3b)x - 12ab = 0
उत्तर
We have been given
ax2 + (4a2 - 3b)x - 12ab = 0
ax2 + 4a2x - 3bx - 12ab = 0
ax(x + 4a) - 3b(x + 4a) = 0
(ax - 3b)(x + 4a) = 0
Therefore,
ax - 3b = 0
ax = 3b
`x=(3b)/a`
or
x + 4a = 0
x = -4a
Hence, `x=(3b)/a` or x = -4a
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