Advertisements
Advertisements
प्रश्न
Solve the following systems of equations:
4u + 3y = 8
`6u - 4y = -5`
उत्तर
Taking `1/x = u` then given equations become
4u + 3y = 8 ......(i)
6u - 4y = -5 ..........(ii)
From (i), we get
4u = 8 -3y
`=> u = (8 - 3y)/4`
Substituting u = `(8 - 3y)/4` in (ii) we get
From (ii), we get
`6((8-3y)/4) - 4y = -5`
`=> (3(8 - 3y))/4 - 4y = -5`
`=> (24 - 9y)/2 - 4y= -5`
`=> (24 - 9y - 8y)/2 = -5`
=> 24 - 17y = -10
=> -17y = -10 -24
=> -17y = -34
`=> y = (-34)/(-17) = 2`
Putting y = 2 in u =`(8-3y)/4` we get
`u = (8 - 3xx 2)/4 = (8-6)/4 = 2/4 = 1/2`
Hence x = 1/u = 2
So, the solution of the given system of equation is x 2, y
APPEARS IN
संबंधित प्रश्न
A train travels at a certain average speed for a distance of 54 km and then travels a distance of 63 km at an average speed of 6 km/h more than the first speed. If it takes 3 hours to complete the total journey, what is its first speed?
Which of the following pairs of linear equations has unique solution, no solution, or infinitely many solutions. In case there is a unique solution, find it by using cross multiplication method
x – 3y – 3 = 0
3x – 9y – 2 = 0
Which of the following pairs of linear equations has unique solution, no solution or infinitely many solutions? In case there is a unique solution, find it by using cross multiplication method
2x + y = 5
3x + 2y = 8
Solve each of the following systems of equations by the method of cross-multiplication
3x + 2y + 25 = 0
2x + y + 10 = 0
Solve each of the following systems of equations by the method of cross-multiplication
`x/a = y/b`
`ax + by = a^2 + b^2`
Solve each of the following systems of equations by the method of cross-multiplication :
`x(a - b + (ab)/(a - b)) = y(a + b - (ab)/(a + b))`
`x + y = 2a^2`
Solve each of the following systems of equations by the method of cross-multiplication :
2(ax – by) + a + 4b = 0
2(bx + ay) + b – 4a = 0
Solve each of the following systems of equations by the method of cross-multiplication :
`(ax)/b - (by)/a = a + b`
ax - by = 2ab
Solve the following pair of equations:
`1/(2x) - 1/y = -1, 1/x + 1/(2y) = 8, x, y ≠ 0`
Ankita travels 14 km to her home partly by rickshaw and partly by bus. She takes half an hour if she travels 2 km by rickshaw, and the remaining distance by bus. On the other hand, if she travels 4 km by rickshaw and the remaining distance by bus, she takes 9 minutes longer. Find the speed of the rickshaw and of the bus.
