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Pair of Linear Equations in Two Variables
- Introduction to linear equations in two variables
- Graphical Method
- Substitution Method
- Elimination Method
- Cross - Multiplication Method
- Equations Reducible to a Pair of Linear Equations in Two Variables
- Consistency of Pair of Linear Equations
- Inconsistency of Pair of Linear Equations
- Algebraic Conditions for Number of Solutions
- Simple Situational Problems
- Pair of Linear Equations in Two Variables
- Relation Between Co-efficient
Quadratic Equations
- Quadratic Equations
- Solutions of Quadratic Equations by Factorization
- Solutions of Quadratic Equations by Completing the Square
- Nature of Roots of a Quadratic Equation
- Relationship Between Discriminant and Nature of Roots
- Situational Problems Based on Quadratic Equations Related to Day to Day Activities to Be Incorporated
- Application of Quadratic Equation
Arithmetic Progressions
Coordinate Geometry
Lines (In Two-dimensions)
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- Division of a Line Segment
- Construction of Tangents to a Circle
- Constructions Examples and Solutions
Geometry
Triangles
- Similar Figures
- Similarity of Triangles
- Basic Proportionality Theorem (Thales Theorem)
- Criteria for Similarity of Triangles
- Areas of Similar Triangles
- Right-angled Triangles and Pythagoras Property
- Similarity of Triangles
- Application of Pythagoras Theorem in Acute Angle and Obtuse Angle
- Triangles Examples and Solutions
- Concept of Angle Bisector
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- Ratio of Sides of Triangle
Circles
Trigonometry
Introduction to Trigonometry
- Trigonometry
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- Trigonometric Ratios
- Trigonometric Ratios and Its Reciprocal
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Some Applications of Trigonometry
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Statistics and Probability
Statistics
Probability
Internal Assessment
Cross Multiplication Method
Cross Multiplication Method- To understand this method properly, we shall take the help of an example
`4x+2y-7=0` ......eq1
`5x+3y-8=0` ......eq2
While practising this method, if we want to find the value of a particular variable, we will take that variable as a numerator, and the denominator will be the subtraction between the cross multiplication of coefficients of the remaining two variables. In this case, it will be like
`x/"(2×-8)-(-7×3)"`
`y/"(4×-8)-(-7×5)"`
`1/"(4×3)-(2×5)"`
All of them are equal to each other, so to find the value of x,
`x/"(2×-8)-(-7×3)" = 1/"(4×3)-(2×5)"`
`x/"-16+21"=1/"12-10"`
`x/5= 1/2`
`x=5/2`
To find the value of y,
`y/"(4×-8)-(-7×5)"= 1/"(4×3)-(2×5)"`
`y/"-32+35" = 1/"12-10"`
`y/3 = 1/2`
`y= 3/2`
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