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प्रश्न
Solve the following systems of equations:
`sqrt2x + sqrt3y = 0`
`sqrt3x - sqrt8y = 0`
उत्तर
`sqrt2x + sqrt3y = 0`....(i)
`sqrt3x - sqrt8y = 0` ....(ii)
From equation (i), we obtain:
`x = (-3sqrty)/sqrt2` ....(iii)
Substituting this value in equation (ii), we obtain:
`sqrt3 ((- sqrt3y)/sqrt2) - sqrt8y = 0`
`- (3y)/sqrt2 - 2sqrt2y = 0`
`y (-3/sqrt2 - 2sqrt2) = 0`
y = 0
Substituting the value of y in equation (iii), we obtain:
x= 0
`:. x = 0, y = 0`
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