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प्रश्न
Solve the following systems of equations:
`3x - (y + 7)/11 + 2 = 10`
`2y + (x + 10)/7 = 10`
उत्तर
The given systems of equation is
`3x - (y + 7)/11 + 2 = 10` ......(i)
`2y + (x + 11)/7 = 10` .....(ii)
From (i), we get
`(33x - y - 7 + 22)/11 = 10`
`=> 33x - y + 15 = 10 xx 11`
`=> 33x + 15 - 110 = y`
=> y = 33x - 95
From (ii) we get
`(14y + x + 11)/7 = 109`
`=> 14y + x + 11 = 10 xx 7`
`=> 14y + x + 11 = 70`
=> 14y + x = 70 - 11
=> 14y + x = 59 ...(iii)
Substituting y = 33x - 95 in (iii), we get
14 (33x - 95) + x = 59
`=> 462x - 1330 + x = 59`
`=> 463x = 59 + 1330`
=> 463x = 1389
`=> x = 1389/463 = 3`
Putting x = 3, in y = 33x - 95, we get
`y = 33 xx 3 - 95`
`=> y = 99- 95`
= 4
y = 4
Hence, solution of the given system of equation is x =3, y = 4.
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