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प्रश्न
Solve the following systems of equations:
`4/x + 3y = 14`
`3/x - 4y = 23`
उत्तर
`4/x + 3y = 14`
`3/x - 4y = 23`
Let `1/x = p`
The given equations reduce to:
4p + 3y = 14
=> 4p + 3y - 14 = 0 ...(1)
3p - 4y = 23
=> 3p - 4y - 23 = 0 ....(2)
Using cross-multiplication method, we obtain
`p/(-69-56) = y/(-42 - (-92)) = 1/(-16 - 9)`
`p/(-125) = y/50 = (-1)/25`
p = 5 , y = -2
`:. p = 1/x = 5`
`x = 1/5`
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