Advertisements
Advertisements
प्रश्न
Solve the following system of equations graphically:
6x - 3y + 2 = 7x + 1
5x + 1 = 4x - y + 2
Also, find the area of the triangle formed by these lines and x-axis in each graph.
उत्तर
The given system of equations are
6x - 3y + 2 = 7x + 1 and 5x + 1 = 4x - y + 2
Now, 6x - 3y + 2
= 7x + 1 ....(1)
⇒ x = 1 - 3y
Corresponding values of x and y can be tabulated as :
x | 1 | -2 | 4 |
y | 0 | 1 | -1 |
Plotting points (1, 0), (-2, 1) and (4, -1) joining them, we get a line l1 which is the graph of equation (i).
Again, 5x + 1 = 4x - y + 2 ....(ii)
⇒ x = 1 - y
Corresponding values of x and y can be tabulated as :
x | -1 | 3 | -2 |
y | 2 | -2 | 3 |
Plotting points (-1, 2), (3, -2) and (-2, 3) joining them, we get a line l2 which is the graph of equation (ii).
The two lines l1 and l2 intersect at a point P(1, 0).
∴ x = 1, y = 0 is the solution of the given system of equations.
Since both the lines l1 and l2 are intersecting each other at X-axis, no triangle is formed by these lines with X-axis.
APPEARS IN
संबंधित प्रश्न
Solve graphically the simultaneous equations given below. Take the scale as 2 cm = 1 unit on both the axes.
x - 2y - 4 = 0
2x + y = 3
The cost of manufacturing x articles is Rs.(50 + 3x). The selling price of x articles is Rs. 4x.
On a graph sheet, with the same axes, and taking suitable scales draw two graphs, first for the cost of manufacturing against no. of articles and the second for the selling price against the number of articles.
Use your graph to determine:
The profit or loss made when (a) 30 (b) 60 articles are manufactured and sold.
Solve the following equations graphically :
2x + 4y = 7
3x + 8y = 10
Solve the following equations graphically :
x + 4y + 9 = 0
3y = 5x - 1
Solve the following equations graphically :
`2 + (3y)/x = (6)/x`
`(6x)/y - 5 = (4)/y`
Solve the following system of equations graphically
x - y + 1 = 0
4x + 3y = 24
Solve graphically
3x + 2y = 4, 9x + 6y – 12 = 0
Solve graphically
`x/2 + y/4` = 1, `x/2 + y/4` = 2
Solve graphically
x – y = 0, y + 3 = 0
Solve graphically
y = 2x + 1, y + 3x – 6 = 0